36x^2+26x-196=0

Solution for 36x^2+26x-196=0 equation:

36x^2+26x-196=0

a = 36; b = 26; c = -196;
Δ = b2-4ac
Δ = 262-4·36·(-196)
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28900}=170$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-170}{2*36}=\frac{-196}{72}
=-2+13/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+170}{2*36}=\frac{144}{72}
=2
$